Exercise 69

The points on the Cartesian plane (2, 3) and (3, 5) satisfy the equation:

\[ ax + by + 1 = 0 \]

Then the value of \(a\) is:

  1. \( -2 \)

  2. \( 1 \)

  3. \( 7 \)

  4. \( 2 \)

  5. \( -1 \)

Try to solve it before checking the answer.
  1. \( -2 \)

Replacing the coordinates of the two points in the equation \( ax + by + 1 = 0 \) we obtain the following system:

\( \boldsymbol{(1)} \hspace{2em} 2a + 3b + 1 = 0 \)

\( \boldsymbol{(2)} \hspace{2em} 3a + 5b + 1 = 0 \)

Multiplying equation (1) by 5 and equation (2) by -3, we obtain:

\( \boldsymbol{(3)} \hspace{2em} 10a + 15b + 5 = 0 \)

\( \boldsymbol{(4)} \hspace{2em} -9a – 15b – 3 = 0 \)

Adding (4) and (5) we obtain:

\[ a + 2 = 0 \Rightarrow \boldsymbol{a = -2} \]