Exercise 60
In a circle with radius \( r \), \( \frac{1}{ \pi} \) times the circumference is:
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twice the diameter
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the radius
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the semi circumference
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the diameter
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half the radius
Try to solve it before checking the answer.
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the diameter
The length of the circumference is \( 2\pi r \). Hence:
\[ \frac{1}{\pi} (2 \pi r) = 2 r = \text{diameter} \]